At a certain temperature the reaction
CO2(g) + H2(g) ↔ CO(g) + H2O(g) has Kc = 2.50.
If 2.00 mol of carbon dioxide and 1.5 mol of hydrogen are placed in a 5.00 L vessel and equilibrium is established, what will be the concentration of carbon monoxide?

Respuesta :

The concentration of carbon monoxide at equilibrium is 0.209 M.

Concentration of each gas

CO2 = 2 mol/5 L = 0.4

H2 = 1.5 mol/5L = 0.3

ICE table

Create ICE table as shown below

        CO2(g)    +     H2(g) ↔       CO(g)    +     H2O(g)

I          0.4               0.3                0                  0

C        - x                 - x                 x                   x

E        0.4 - x           0.3 - x           x                   x

Kc = [CO][H₂O] / [CO₂][H₂]

2.5 = (x²)/(0.4 - x)(0.3 - x)

x² = 2.5(0.4 - x)(0.3 - x)

x² = 2.5(0.12 - 0.7x + x²)

x²  = 0.3 - 1.75x + 2.5x²

0 = 1.5x² - 1.75x + 0.3

solve the quadratic equation using formula method;

x = 0.209

Thus, the concentration of carbon monoxide at equilibrium is 0.209 M.

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