The graph shows a system of inequalities.

Graph of two inequalities. One is a dashed line increasing from left to right passing through negative 5 comma 0 and 0 comma 5, and it has shading above the line. The second is a dashed upward opening parabola with a vertex at negative 2 comma negative 9 and x-intercepts at negative 5 comma 0 and 1 comma 0. This parabola is shaded on the inside.

Which system is represented in the graph?

y > x2 + 4x – 5
y > x + 5
y < x2 + 4x – 5
y < x + 5
y ≥ x2 + 4x – 5
y ≤ x + 5
y > x2 + 4x – 5
y < x + 5

The system of inequalities having the given feasible regions and points at (-5, 0), and (0, 5), and (-2, -9), (-5, 0), and (1, 0) is the option;

y > x² + 4•x - 5

y > x + 5

How can the required system of inequalities be found?

The coordinates of the given points on the linear inequality are;

(-5, 0), and (0, 5)

Slope, m, of the linear inequality is therefore;

m = (5 - 0)/(0 - (-5)) = 1

The equation of the inequality is therefore;

y - 0 > 1•(x - (-5)) = x + 5

Which gives;

y > x + 5

Quadratic Inequality;

The coordinates of the points on the quadratic inequality are;

Vertex point = (-2, -9)

x-intercept = (-5, 0), and (1, 0)

Therefore, we have;

y > (x + 5)•(x - 1) = x² + 4•x - 5

y > x² + 4•x - 5

The correct option is therefore;

y > x² + 4•x - 5

y > x + 5

Learn more about inequalities here!

https://brainly.com/question/24372553

#SPJ1