Question

The molar mass of sulfur (s) is 32.06 g/mol.
calculate the mass in grams of a sample of s containing 2.01 x 10^24 atoms.

Answer 1

Answer:

mass = 107.04 g

Explanation:

The formula for mass is:
$\boxed{mass = mole \space\ no. \times \space\ molar \space\ mass}$.

In this case:

• molar mass = 32.06 g/mol

• mole no. = $\frac{no. \space\ of \space\ atoms}{Avogadro's \space\ number}$

               = $\frac{2.01 \times 10^{24}}{6.02 \times 10^{23}}$

               = 3.339 mol

Substituting these values into the formula for mass :

mass = 3.339 mol × 32.06 g/mol

         = 107.04 g

Answer 2

The answer is 107.04 g.

The first step is to find the number of moles of sulfur.

Number of moles = No. of atoms ÷ Avogadro No.

• (2.01 × 10²⁴) ÷ (6.02 × 10²³)
• 0.3339 × 10
• 3.339 moles

Now, to find the mass, multiply the number of atoms by the molar mass.

• 3.339 × 32.06
• 107.04 g