Question

1. There are 42 grams of sugar (C12H22O11) in a can of pop (342mL). Use this information (where necessary) to answer the following questions:

a) How many moles of sugar are there in the pop (3 marks)?

b) If a mole of sugar costs 90 cents, what is the value of the sugar in a can of pop (3 marks)?

c) How many particles of sugar are there in the pop (3 marks)?

d) What is the concentration (mol/L) of the sugar in the pop (3 marks)?

Answer 1

1. The mole of sugar in the pop is 0.123 mole

2. The value of the sugar in the pop is 11.07 cents

3. The number of particles of the sugar in the pop is 0.74×10²³ particles

4. The concentration of the sugar in the pop is 0.36 mol/L

1. How to determine the mole of the sugar

• Mass of sugar (C₁₂H₂₂O₁₁) = 42 g
• Molar mass of sugar (C₁₂H₂₂O₁₁) = 342 g/mol
• Mole of sugar (C₁₂H₂₂O₁₁) =?

Mole = mass / molar mass

Mole of sugar (C₁₂H₂₂O₁₁) = 42 / 342

Mole of sugar (C₁₂H₂₂O₁₁) = 0.123 mole

2. How to determine the value of the sugar

• Cost per mole = 90 cents
• Cost of 0.123 mole of sugar =?

1 mole of sugar = 90 cents

Therefore,

0.123 mole of sugar = 0.123 × 90

0.123 mole of sugar = 11.07 cents

3. How to determine the number of particles of the sugar

From Avogadro's hypothesis,

1 mole of sugar = 6.02×10²³ particles

Therefore,

0.123 mole of sugar = 0.123 × 6.02×10²³

0.123 mole of sugar = 0.74×10²³ particles

4. How to determine the concentration of the sugar

• Mole of sugar (C₁₂H₂₂O₁₁) = 0.123 mole
• Volume = 342 mL = 342 / 1000 = 0.342 L
• Concentration of sugar =?

Concentration = mole / Volume

Concentration of sugar = 0.123 / 0.342

Concentration of sugar = 0.36 mol/L

Learn more about Avogadro's number:

https://brainly.com/question/26141731

Learn more about molarity:

https://brainly.com/question/9468209

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