Question

Select the correct answer. sean used cross multiplication to correctly solve a rational equation. he found one valid solution and one extraneous solution. if 1 is the extraneous solution, which equation could he have solved?

Answer 1

The equation that Sean woul have solved using the cross multiplication would be option a.

How to solve the question through the use of cross multiplication

$\frac{10}{x^2-1} =\frac{15}{3x-3}$

We have to open the equation by using cross multiplication

10(3x - 3) = 15(x² - 1)

= 30x - 30 = 15x² - 15

we would have to factorize

30(x-1) = 15(x-1)(x+1)

We have to divide by 15(x-1)

2 = x + 1

take the like terms

2 -1 = x

x = 1

Hence the equation that has the extraneous solution is option a because the solution is 1.

Read more on extraneous equations here:

https://brainly.com/question/19904306

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