Question

Hurry A total of $6000 is invested: part at 5% and the remainder at 10%. How much is invested at each rate if the annual interest is $510?

Answer 1

Answer:

Step-by-step explanation:

We know a total of 6000 is being turned into 510, in two accounts which equal to 15%, to find how much is in each account we can create the following equation:

$5x+10x=510$

Solve for x

$15x=510\\x=34$

Now multiply x by the corresponding percentages to find how much was invested into each percentage.

$34*5=170$

$34*10=340$

Therefore we now know that 170 dollars was invested into the 5% division, and 340 dollars was invested into the 10% division.

We can of course check our answer by adding 170+340 which equals our original investment of 510.