The remainder when f(x)=−2x3+x2−4x+1 is divided by x+3. is 76
How to determine the remainder?
The function is given as:
f(x)=−2x3+x2−4x+1 is divided by x+3.
Set the divisor to 0
x + 3 = 0
Solve for x
x = -3
Calculate f(-3)
f(-3)=−2(-3)^3+(-3)^2 − 4(-3) + 1
Evaluate the expression
f(-3)= 76
Hence, the remainder when f(x)=−2x3+x2−4x+1 is divided by x+3. is 76
Read more about remainder theorem at:
https://brainly.com/question/13328536
#SPJ1
