Answer:
156.16 gm of ice
Explanation:
I will assume the ice starts at 0 C
As the ice melts, it produces water at 0 C so we do not need to calculate THAT water being cooled....only the 356 ml being cooled to 0 C
356 gm * 4.186 j/gm-c * (35 c) = 52157.56 j
this is the heat absorbed by the melting ice
x gm * 334 j / gm = 52157.56 j (334 j/gm is heat of fusion of water)
x = 156.16 gm of ice required