Question

A fourth-degree polynomial with a leading coefficient of 1 has gone through several transformations, including a vertical compression by a scale factor of 1/3 and a reflection across the x-axis. Two of the zero polynomials are -i and 3i.

Find a y-intercept of this polynomial, if it exists

Answer 1

The y-intercept of the resulting polynomial is equal to - 3.

How to derive a fourth-degree polynomial generated by rigid transformations

Herein we assume that the other two zeros of the polynomial are i and - i 3, otherwise the polynomial will have at least a complex number as coefficient of the expression. This is because we need to find values from a Cartesian plan, whose ordered pairs are real numbers.

Initially, we have the following expression by algebra properties:

f(x) = (x + i) · (x - i) · (x + i 3) · (x - i 3)

f(x) = (x² + 1) · (x² + 9)

f(x) = x⁴ + 10 · x² + 9

Then, we proceed to use the two rigid transformations described in the statement. Please notice that rigid transformations are transformations applied on polynomials such that Euclidean distance is conserved:

Vertical compression

f'(x) = (1 / 3) · f(x)

f'(x) = (1 / 3) · (x⁴ + 10 · x² + 9)

f'(x) = (1 / 3) · x⁴ + (10 / 3) · x² + 3

Reflection across the x-axis

g(x) = - f'(x)

g(x) = - (1 / 3) · x⁴ - (10 / 3) · x² - 3

The y-intercept is found for x = 0:

g(0) =  - (1 / 3) · 0⁴ - (10 / 3) · 0² - 3

g(0) = - 3

The y-intercept of the resulting polynomial is equal to - 3.

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