Triangle ABC has been rotated 90° to create triangle DEF. Write the equation, in slope-intercept form, of the side of triangle ABC that is perpendicular to segment EF. You must show all work to receive credit.

Triangle ABC has been rotated 90 to create triangle DEF Write the equation in slopeintercept form of the side of triangle ABC that is perpendicular to segment E class=

Respuesta :

the equation in the slope-intercept of the side of triangle ABC that is perpendicular to segment EF is y = x + 1

How to determine the equation

From the figure given, we can deduce the coordinates of the sides

For A

A ( 4,2)

For B

B ( 4, 5)

C ( 1, 2)

D ( 2, -4 )

E  ( 5, -4)

F ( 2, -1)

The slope for BC

Slope = [tex]\frac{y2 - y1}{x2 - x1}[/tex]

Substitute the values for both B and C coordinates, we have

Slope = [tex]\frac{2- 5}{1 - 4}[/tex]

Find the difference for both the numerator and denominator

Slope = [tex]\frac{-3}{-3}[/tex]

Slope = 1

We have the rotation for both point ( 0, 1)

y - y1 = m ( x - x1)

The values for y1 and x1 are 1 and 0 respectively and the slope m is 1

Substitute the values

y - 1 = 1 ( x - 0)

y - 1 = x

Make 'y' the subject of formula

y = x + 1

Thus, the equation in the slope-intercept of the side of triangle ABC that is perpendicular to segment EF is y = x + 1

Learn more about linear graphs here:

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