Question

What is the molality of a nh₄no₃ solution of 125 g of nh₄no₃ (80.0434 g/mol) in 275 g of water (18.0153 g/mol)?

Answer 1

The molality of the given solution is 5.67 mol/kg

You may calculate the molality of a solution to find out how many moles of solute you obtain per kilogram of solvent. Mol/kg is a typical molality measurement unit in chemistry. One molal is another way to refer to a solution with a concentration of 1 mol/kg. Molar mass must be represented in kg/mol rather than the more common g/mol or kg/kmol when using the unit mol/kg. The formula is as follows:

Molality = $\frac{moles of solute}{kilogram of solvent}$

First we need to find moles of solute ;

moles of solutes = $\frac{given mass}{molecular mass}$

moles = 125 / 80.0434

moles of solute = 1.56

Now, molality is ;

molality = 1.56 / 0.275

molality = 5.67 mol/kg

Therefore, The molality of the given solution is 5.67 mol/kg

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