Question

90cm3 of 1 m hcl solution and 10cm3 of 0.5 m naoh solution are mixed together. the concentration of hcl contained in the final solution

Answer 1

The concentration of HCl contained in the final solution is 0.95 M.

Calculation:

Here, we use the dilution formula, which is,

M (V₁ + V₂) = M₁V₁ + M₂V₂

where,

M = resultant concentration

M₁ = concentration of HCl

V₁ = volume of HCl

M₂ = concentration of NaOH

V₂ = volume of NaOH

Given,

M₁ = 1 M

V₁ = 90 cm³ = 90 mL

M₂ = 0.5 M

V₂ = 10 cm³ = 10 mL

To find,

M =?

Put the values in the above formula,

M (V₁ + V₂) = M₁V₁ + M₂V₂

M (90 + 10) = (1 × 90) + (0.5 × 10)

M × 100 = 90 + 5

M × 100 = 95

M = 95/100

M = 0.95 M

Therefore, the concentration of HCl contained in the final solution is 0.95 M.

Learn more about the dilution formula here:

https://brainly.com/question/27622467

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