See attachment for the graph of the cosine function f(x) = 5 cos(π/2x) - 1
From the question, the given parameters are:
Amplitude, A = 5
Vertical shift, D = -1
Period, T = 4
A cosine function is represented as:
f(x) = A cos(B(x + C)) + D
Where
Amplitude = A
Period = T
Horizontal shift = C
Vertical shift = D
Since the horizontal shift is not stated in the question, we can assume that the horizontal shift is 0
i.e. C = 0
So, the equation of the cosine function becomes
f(x) = A cos(Bx) + D
Calculate the value of B using
B = 2π/T
So, we have:
B = 2π/4
Evaluate
B = π/2
So, we have:
f(x) = A cos(π/2x) + D
Substitute the known values of A and D in the above equation
f(x) = 5 cos(π/2x) - 1
Next, we plot the graph of the cosine function on a graphing tool
See attachment for the graph of the cosine function f(x) = 5 cos(π/2x) - 1
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