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The 8 cm circle radius and the location of the circle X gives the following values;
(a) tan(<XAB) = -(r - 8)/(2•r + 4) = (8 - r)/8
Which gives;
(b) <XAB is approximately 0.644 radians
(c) The area of the shaded region is approximately 3.107 cm²
8 × (8 - r) = 0.5 × 16 × (8 + r) × sin(A)
(8 - r) = (8 + r) × sin(A)
sin(A) = (8 - r)÷(8 + r)
(8 - r)² = 8² + (8 + r)² - 2×8×(8 + r)×cos(A)
16×(8 + r)×cos(A) = (8² + (8 + r)²) - (8 - r)²
Which gives;
cos(A) = ((8² + (8 + r)²) - (8 - r)²) ÷ (16×(8 + r))
cos(A) = (2•r + 4)/(r + 8)
tan(A) = ((8 - r)÷(8 + r))/( (2•r + 4)/(r + 8))
tan(A) = -(r - 8)/(2•r + 4) = (8 - r)/8
(8 - r)/(2•r + 4) = (8 - r)/8
8 = 2•r + 4
2•r + 4 = 8
Therefore;
(b) sin(A) = (8 - r)÷(8 + r)
sin(A) = (8 - 2)÷(8 + 2) = 0.6
Therefore;
<XAB = <A = arcsin(0.6) ≈ 0.644 rad
<XAB in degrees ≈ 36.87°
Angle at sector PXQ = 180° - 2 × (36.87°) ≈ 106.26°
Area of sector PXQ ≈ (106.26°/(360°)) × π × 2²
(106.26°/(360°)) × π × 2² ≈ 3.71
Area of sector APO ≈ (36.87°/(360°)) × π × 8² ≈ 20.59
Area of triangle AXB = 8 × (8-2) = 48
The shaded area is therefore;
48 - (2×20.59 + 3.71) ≈ 3.107
Learn more about the trigonometric ratios here:
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a) The radius of the small circle is 2 centimeters.
b) The measure of the angle XAB is approximately equal to 51.340°.
c) The area of the shaded region is approximately equal to 2.423 square centimeters.
In this question we must analyze a geometrical system formed by three semicircles and a circle. The small circle touches the two side semicircles tangentially at points P and Q and the uppermost section of it also tangent to the central semicircle (point R).
(a) Therefore, we have to solve the following system of equations:
8² + h² = (8 + r)² (1)
h + r = 8 (2)
By (2) in (1):
8² + (8 - r)² = (8 + r)²
32 · r = 64
r = 2
The radius of the small circle is 2 centimeters.
(b) The measure of the angle XAB is found by trigonometric functions:
tan m ∠ XAB = OX / AO
tan m ∠ XAB = 10 / 8
m ∠ XAB ≈ 51.340°
The measure of the angle XAB is approximately equal to 51.340°.
(c) The area of the shaded region if the area of the triangle AXB minus the areas of the three circular sections, that is:
A = 0.5 · (16 cm) · (10 cm) · sin 51.340° - (51.340° / 180°) · π · (8 cm)² - 0.5 · (77.320° / 180°) · π · (2 cm)²
A ≈ 2.423 cm²
The area of the shaded region is approximately equal to 2.423 square centimeters.
To learn more on triangles: https://brainly.com/question/2773823
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