Answer:
2nd option, x > 1.10
Step-by-step explanation:
[tex]7e^{2x}-5 > 58[/tex]
Add 5 to both sides,
[tex]7e^{2x}-5+5 > 58 +5\\7e^{2x} > 63[/tex]
Divided both sides by 7,
[tex]\frac{7e^{2x}}{7} > \frac{63}{7}[/tex]
[tex]e^{2x} > 9[/tex]
Apply Exponent Rule,
[tex]2x > 2ln(3)[/tex]
[tex]\frac{2x}{2} > \frac{2ln(3)}{2}[/tex]
x > ln(3) or x > 1.09861
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