Coach Bennet’s high school basketball team has 14 players, consisting of six juniors and eight seniors. Coach Bennet must select three players from the team to participate in a summer basketball clinic.

Using the permutation formula, the number of different options for the top three finishers is given as follows:
[tex]P_{14,3} = \frac{14!}{11!} = 2184[/tex]
The order in which the players are chosen is important, as A, B, C is a different outcome than C,B,A for example, hence the permutation formula is used to solve this question.
The number of possible permutations of x elements from a set of n elements is given by:
[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]
In this problem, 3 students will be chosen from a set of 14, hence the number of ways is:
[tex]P_{14,3} = \frac{14!}{11!} = 2184[/tex]
More can be learned about the permutation formula at https://brainly.com/question/25925367
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