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The comparison of the number of x-intercepts in the graph of f(x)=x^2 to the number of x-intercepts in the graph of g(x)=(x+1)^2 how that:

  • x-intercept of f(x) is 0
  • x-intercept of g(x) is -1
  • g(x) is the image of f(x) after translating it 1 unit to the left.

How to illustrate the information?

A graph is  a diagram representing a system of connections or interrelations among two or more things by a number of distinctive dots, lines, bars, etc. It depicts a series of points, discrete or continuous, as in forming a curve or surface, each of which represents a value of a given function.

In the graph f(x) = x²

The x-intercept = 0 ⇒ ∵ f(x) = 0 ⇒ ∴ x² = 0 ⇒ x = 0

The vertex of the parabola is (0 , 0). The vertex of a parabola is the point where the parabola crosses its axis of symmetry.

In the graph g(x) = (x + 1)²

The x-intercept = 0 ⇒ ∵ g(x) = 0 ⇒ ∴ (x + 1)² = 0.  The x-intercept is the point at which the graph of an equation crosses the x-axis.

x + 1 = 0 ⇒ x = -1

The vertex of the parabola is (-1 , 0). Therefore g(x) is the image of f(x) after translating it 1 unit to the left

Learn more about graph on:

https://brainly.com/question/2646528

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