Respuesta :

answer is:
3(2x+5)*(3x-1)

Steps for Factoring:

1) Find CM (common factor) for the expression: 3

   Factor out 3 =>

   [tex]3(6x^{2}+13x-5)[/tex]

2)Factor the above expression by grouping:

  The expression needs to be written as [tex]6x^{2} + ax+ bx -5[/tex]

 a and b should add up to 13 and multiply up to -30 (6 × -5)

By Guess & Check we find that the pair is a = -2 and b = 15 (-2+15; -2 × 15)

3) Now we can rewrite [tex](6x^{2}+13x-5)[/tex] as [tex](6x^{2} -2x)+(15x-5)\\[/tex]

Factor out 2x in the first group and 5 in the second group:

[tex]2x(3x-1)+5(3x-1)\\[/tex]

As 3x-1 is on both sides, now we can do the operation: 2x+5 (distributive property)

(3x-1) (2x+5)

The answer is 3(3x-1) (2x+5)

Hope it helps!

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