Question

Use the Fundamental Counting Principle to solve.
There are 9 performers who will present their comedy acts this weekend at a comedy club. One of the performers
insists on being the last stand-up comic of the evening. If this performer's request is granted, how many different
ways are there to schedule the appearances?

There are ways to schedule the appearances.
(Simplify your answer.)
GECOD

Answer 1

$number \: of \: performances = 9 \\ note = \\ one \: insists \: on \: being \: last \\ number \: of \: flexible \: performances = 9 - 1 = 8 \\ \\ c( \gamma ) = 8P8 \times 1 \\ c( \gamma ) = 8! \\ c( \gamma ) = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \\ c( \gamma ) = 40320 \: ways$