Answer:
Step-by-step explanation:
eq. of any line perpendicular to 5x+6y=-6 is
5y-6x=c
where c is a constant.
it passes through (-2,-1) so
5(-1)-6(-2)=c
c=-5+12=7
so reqd. eq. is 5y-6x=7
or 6x-5y=-7
or
slope of given line =-5/6
slope of reqd. line=6/5
eq. of line through (-2,-1) with slope 6/5 is
y+1=6/5(x+2)
5y+5=6x+12
5y=6x+12-5
or 5y=6x+7
or
6x-5y=-7
