Question

What are the solutions to the equation below?
2x^2 - x + 1 = 0
1/4 - startroot 5 endroot/ 4 and 1/4 + startroot 5 endroot / 4
1/4 - startroot 7 endroot/ 4 and 1/4 + startroot 7 endroot/ 4
1/4 - startroot 7 endroot/ 4 i and 1/4 + startroot 7 endroot/4 i
1/4 - startroot 5 endroot/ 4 i and 1/4 + startroot 5 endroot/4 i

Answer 1

The solutions of the given quadratic equation is;  (1/4) + √7i/4 and  (1/4) - √7i/4

How to find the solution of a quadratic equation?

We are given the quadratic equation as;

2x² - x + 1 = 0

To solve this to find the root, we will use the quadratic formula which is given by;

x = [-b ± √(b² - 4ac)]/2a

Now, from the given quadratic equation, we can say that the values of a, b and c are;

a = 2; b = -1 and c = 1

Thus;

x = [-(-1) ± √((-1)² - 4(2 * 1))]/2(2)

x =  [1 ± √(1 - 8)]/4

x = [1 ± √(-7)]/4

x = (1/4) ± √7i/4

Thus;

x = (1/4) + √7i/4 and  (1/4) - √7i/4

Read more about roots of quadratic equations at; https://brainly.com/question/1214333

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