A wire coil inside a generator has 150 square loops and an area equal to 0.042 m2.
The coil rotates one-quarter turn in 1.7 ms. If a 0.86 T magnetic field surrounds the
coil, what is the maximum electromotive force induced in the coil

a. 3.2 V
b. 130 V
c. 1600 V
d. 3200 V

Respuesta :

D. The maximum electromotive force induced in the coil is determined as 3,200 V.

Maximum electromotive force induced in the coil

emf(max) = NAB/t

where;

  • N is number of turns
  • B is magnetic field
  • A is area of the coil
  • t is time

Substitute the given parameters and solve for emf

emf(max) = (150 x 0.042 x 0.86) / (1.7 x 10⁻³)

emf(max) = 3,187.1 V

emf(max) ≈ 3,200 V

Thus, the maximum electromotive force induced in the coil is determined as 3,200 V.

Learn more about emf here: https://brainly.com/question/24158806

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