The edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.
Volume of molybdenum
V = (zm/ρN)
where;
- z is 2 for cubic unit cell
- m is mass of the molybdenum
- ρ is density of the molybdenum
V = (2 x 95.96) / (10.28 x 6.02 x 10²³)
V = 3.10 x 10⁻²³ cm³
Edge length of the unit cell
a³ = V
a = (V)^¹/₃
a = ( 3.10 x 10⁻²³)^¹/₃
a = 3.142 x 10⁻⁸ cm
a = 3.142 x 10⁻¹⁰ m
a = 314.2 x 10⁻¹² m
a = 314.2 pm
Thus, the edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.
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