Matthew is flying with his jet pack at 100m/min. A strong wind has blown him 10m east of his intended flight path in 2 minutes. By how many degrees is Matthew off his flight path? Include a diagram.

Mathew's speed of 100 m/min, and the distance of 10 m. east to which he is blown by the wind gives the angle in degrees Mathew is blown off his path as approximately 2.86°.

How can the angle of deflection be found from the given speeds?

The given parameters are;

Speed at which Mathew is flying = 100 m/min

Distance and direction in which the strong wind blows him = 10 m. east

Time it takes the wind to deflect Mathew by 10 m. = 2 minutes

Therefore;

Speed and direction of the wind = 10/2 m/min east

Speed and direction of the wind = 5 m/min east

Mathew's flight path can be represented using a vector diagram (please see attached drawing)

Distance Mathew travels in 2 minutes = 100 m/min × 2 minutes = 200 m.

Tangent of the angle by which Mathew is off his flight path, A, can be found as follows;

tan(A) = 10/200 = 1/20

A = arctan(1/20) ≈ 2.86°

Learn more about vectors here:

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