Question

This is a reaction going on in your muscle cells right this very minute: what is the equilibrium constant for the un-catalyzed reaction?

Answer 1

The equilibrium constant for the un-catalyzed reaction is 0.9

The enzyme triose phosphate isomerase catalyzes the reaction in the forward direction as part of the glycolytic pathway. It follows simple Michaelis-Menten kinetics.

Typical cellular concentrations:

triose phosphate isomerase = 0.1 nM

dihydroxyacetone phosphate = 5 µM

glyceraldehyde-3-phosphate = 2 µM

So, equillibrium constant is

K = $\frac{[P]}{[S]}$

K = $\frac{ glyceraldehyde-3-phosphate}{dihydroxyacetone phosphate}$

Therefore, The equilibrium constant for the un-catalyzed reaction is 0.9

Learn more about equillibrium here;

https://brainly.com/question/25657597

#SPJ4