Question

Starting with the partially balanced equation, ch3cooh(l) ?o2(g)→2co2(g) 2h2o(l) what coefficient should be placed in front of o2 to balance the oxygen atoms?

Answer 1

The coefficient that should be placed in front of O₂ to balance the oxygen atoms is 2.

What is Balanced Chemical Equation ?

The balanced chemical equation is the equation  in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

The given equation is

CH₃COOH (l) + O₂ → 2CO₂ (g) + 2H₂O(l).

Reactant Side               Product Side

C = 2                               C = 2

H = 4                               H = 4

O = 4                               O = 6

The number of atoms of O in the reactant side is 4 and the number of atoms of O in the product side is 6. So multiply by 2 to balance the oxygen atoms.

CH₃COOH (l) + 2O₂ → 2CO₂ (g) + 2H₂O(l).

Reactant Side               Product Side

C = 2                               C = 2

H = 4                               H = 4

O = 6                               O = 6

Now the given equation is balanced the number of atoms in reactant side is equal to the number of atoms in the product side.

Thus from the above conclusion we can say that The coefficient that should be placed in front of O₂ to balance the oxygen atoms is 2.

Learn more about the Balanced Chemical Equation here: https://brainly.com/question/11904811
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