Given:
initial velocity,u=16m/s
final velocity,v=0m/s
acceleration due to gravity,a=9.8 m/s²
height,h=7m
To find:
time taken,t
we can find the time taken by using second equation of motion as well as first equation of motion,so we use first equation of motion.
v=u+at
substitute the values,we get
0=16+(-9.8)×t
-16=-9.8×t
t=-16/-9.8
t=16/9.8
t=1.63s
Therefore,the time to reach the height of 7m is 1.63s
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