An object is thrown upwards with a speed of 16 m/s. how long does it take it to reach a height of 7.0 m on the way up? neglect air resistance.

Respuesta :

Given:

initial velocity,u=16m/s

final velocity,v=0m/s

acceleration due to gravity,a=9.8 m/s²

height,h=7m

To find:

time taken,t

we can find the time taken by using second equation of motion as well as first equation of motion,so we use first equation of motion.

v=u+at

substitute the values,we get

0=16+(-9.8)×t

-16=-9.8×t

t=-16/-9.8

t=16/9.8

t=1.63s

Therefore,the time to reach the height of 7m is 1.63s

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