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The number of three-digit numbers with distinct digits that can be formed using the digits 1, 2, 3, 5, 8, and 9 Is
.The probability
that both the first digit and the last digit of the three-digit number are even numbers is
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Answer 1

Using it's concept, we have that the probability that both the first digit and the last digit of the three-digit number are even numbers is 2/27.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

Considering that there are six numbers, out of which 4 are odd and 2 are even, we have that:

• The first and last digits are even with 2/6 = 1/3 probability.

• The second digit is odd with 4/6 = 2/3 probability.

Hence the desired probability is:

p = 1/3 x 2/3 x 1/3 = 2/27.

More can be learned about probabilities at https://brainly.com/question/14398287

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