(a) The position where particle Q and P meet is 68.75 m.
(b) The velocity with which particle Q is shot is 15 m/s.
The time elapsed before the two particles meet is calculated as follows;
Distance Q - Distance P = Distance between them
Trise = (V - V₀)/g
Trise = (0 - 40) / -10
Trise = 4.0 s
Hmax = V₀t + 0.5gt²
Hmax = 40 x 4 - (0.5)(10)4²
Hmax = 80 m.
h = Hmax - (V² - V₀²)/2g
h = 80 - ((15)²- 0) / 20
h = 68.75 m.
Thus, the position where particle Q and P meet is 68.75 m
Tfall = (V - V₀)/g = (15-0) / 10
Tfall = 1.5 s
Fall time. = Rise time for Q.
h = V₀t + 0.5gt²
h = 80 - 68.75
h = 11.25
V₀ x 1.5 - 5(1.5)² = 11.25
V₀ x 1.5 - 11.25 = 11.25
V₀ x 1.5 = 22.5
V₀ = 22.5 / 1.5
V₀ = 15 m/s
Thus, the velocity with which particle Q is shot is 15 m/s.
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