The speed of the sport car at the time of impact is 6.61 m/s.
What is the frictional force of the two cars?
Frictional force of the two cars = coefficient of kinetic frictin × mass × acceleration of gravity
= 0.8 × (2500+940) × 9.8
= 26970N
What is the acceleration of the skidded cars?
- As per Newton's second law of motion, force = mass × acceleration
- Acceleration= force / mass
= 26,970/3440
= 7.8 m/s²
What is the velocity of the sport car at the time of impact?
- As per Newton's equation of motion, V² - U² = 2aS
- Here, V = 0 m/s, a= -7.8 m/s², S= 2.8 m
- So, 0²-U²= 2×(-7.8)×2.8
=> U = √43.68
= 6.61 m/s
Thus, we can conclude that the speed of the sport car at the time of impact is 6.61 m/s.
Learn more about the Newton's equation of motion here:
brainly.com/question/8898885
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