Question

Consider the ballistic pendulum collision. The projectile, of mass m, is fired into a large block of mass M. (Figure 1)
a) Derive a formula for the fraction of the magnitude of kinetic energy lost
Express your answer in terms of the variables m and M .
b)Evaluate the fraction for m = 18.0 g and M = 380 g .
Express your answer using three significant figures.

Answer 1

The fraction of the magnitude of the kinetic energy lost is $\frac{(change) KE }{KE} = 1 - \frac{m}{m + M }$. = 0.955.

using the law of conservation of momentum,

$mv=(m+M)V$

$V= m ( \frac{1}{M+m} ) v$

kinetic energy lost,

Δ$KE=KE_{i} -KE_{f}$

(see image )

now, for the other part

the fraction of the kinetic energy lost,

ΔKE/ KE = $1- m (\frac{1}{m+M} )$

ΔKE/ KE = $1 - 18 ( \frac{1}{18 + 380 } )$

ΔKE/ KE = 0.955.

what is kinetic energy ?

The energy that an object has as a result of motion is known as kinetic energy. It is stated as the effort needed to transfer a bulk body from rest to the given velocity. The body holds onto the kinetic energy it gained during its acceleration until its speed changes.

Learn more about kinetic energy here:-

https://brainly.com/question/999862

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