Question

Suppose that the breaking strength of a rope (in pounds) is normally distributed, with a mean of 100 pounds and a standard deviation of 16. What is the probability that a certain rope will break before being subjected to 120 pounds? (You may need to use the standard normal distribution table. Round your answer to four decimal places.)

Answer 1

The probability that a certain rope will break before being subjected to 120 pounds is 89.4%.

What is the probability that a certain rope will break before being subjected to 120 pounds?

The probability is calculated as follows:

Mean = 100

Standard deviation = 16

The probability is obtained from the z-score.

x = mean + z-score * standard deviation

120 = 100 + z-score * 16

z-score = 20/16

z-score = 1.25

From normal distribution table, the probability with a z-score of 1.25 is 89.4%

In conclusion, the probability is obtained from the z-score.

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