The pre-image of the triangle has the following vertices: A'(x, y) = (4, 4/3), B'(x, y) = (- 2, 0) and C'(x, y) = (1, 3).
How to find the pre-image of the triangle
In this problem we must use a transformation rule known as dilation, a kind of rigid transformation, to derive the preimage of the triangle, whose formula is:
P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)] (1)
Now we proceed to find the preimage of the triangle: O(x, y) = (0, 0), k = 2/3
Point A'
A'(x, y) = (0, 0) + (2/3) · [(6, 2) - (0, 0)]
A'(x, y) = (4, 4/3)
Point B'
B'(x, y) = (0, 0) + (2/3) · [(- 3, 0) - (0, 0)]
B'(x, y) = (- 2, 0)
Point C'
C'(x, y) = (0, 0) + (2/3) · [(1.5, 4.5) - (0, 0)]
C'(x, y) = (1, 3)
The pre-image of the triangle has the following vertices: A'(x, y) = (4, 4/3), B'(x, y) = (- 2, 0) and C'(x, y) = (1, 3).
To learn more on transformation rules: https://brainly.com/question/9201867
#SPJ1
