please I need to know how to do this !!

[tex]\frac{6xyz}{2xy-y}.\frac{2x^{2}-7x+3 }{3xz - 9z} = 2x[/tex]
The expression can be simplified as follows:
[tex]\frac{6xyz}{2xy-y}.\frac{2x^{2}-7x+3 }{3xz - 9z}[/tex]
Hence,
[tex]\frac{6xyz}{y(2x-1)}.\frac{(x-3)(2x-1)}{3z(x-3)}[/tex]
Therefore.
[tex]\frac{6xyz}{y(2x-1)}.\frac{(2x-1)}{3z}[/tex]
Hence,
[tex]\frac{2xy}{y(2x-1)}.\frac{(2x-1)}1=2x[/tex]
learn more on expression here: https://brainly.com/question/403991
#SPJ1