The total number of ways in which 4 questions can be answered if the first 2 questions have 3 choices and the last 3 have 4 choices = 144 + 192 = 336
We are given;
Total number of objective questions = 5 questions
Number of choices of first 2 questions = 3 choices
Number of choices of last 3 questions = 4 choices
Number of ways of answering the first 2 questions = 3 * 3 = 9 ways
Number of ways of answering the last 3 questions = 4 * 4 * 4 = 64 ways
Total number of ways of answering the five questions = 9 * 64 = 576 ways
Now, she has to answer only 4 which means it can be either 2 of the first and 2 of the last of 1 of the first and 3 of the last.
Thus, total number of ways of answering 4 questions if it is fist 2 and last 2 = 9 * 16 = 144
Total number of ways of answering 4 questions if 1 of the first and 3 of the last = 3 * 64 = 192
The total number of ways in which they can be answered if the first 2 questions have 3 choices and the last 3 have 4 choices = 144 + 192 = 336
Read more about Probability Combinations at; https://brainly.com/question/11732255
#SPJ1
