(i) Make ammonia number of atoms on reactant side is 8 and on product side is 8. (ii) Separate water number of atoms on reactant side is 6 and on product side is 6. (iii) Combust methane number of atoms on reactant side is 9 and number of atoms on product side is 9.
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
(i) Make Ammonia
First we have to write the balanced chemical equation
N₂ + 3H₂ → 2NH₃
Reactant side Product side
N = 2 N = 2
H = 6 H = 6
So total number of atoms on product and reactant side is 8.
(ii) Separate Water
First we have to write the balanced chemical equation
2H₂O → 2H₂ + O₂
Reactant side Product side
H = 4 H = 4
O = 2 O = 2
So total number of atoms on product and reactant side is 6.
(iii) Combust methane
First we have to write the balanced chemical equation
CH₄ + 2O₂ → 2H₂O + CO₂
Reactant side Product side
C = 1 C = 1
H = 4 H = 4
O = 4 O = 4
So total number of atoms on product and reactant side is 9.
Thus from the above conclusion we can say that For each balanced reaction, the total number of atoms are
Reaction Total number of atoms
Reactant side Product side
Make Ammonia 8 8
Separate Water 6 6
Combust Methane 9 9
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: For each balanced reaction, indicate the total number of atoms in the table below.
Reaction Total number of atoms
Reactant side Product side
Make Ammonia _________ __________
Separate Water _________ __________
Combust Methane _________ __________
Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427
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