Respuesta :
Answer:
26
Explanation:
[tex]\int\limits^{25}_{-1} {e^{x-[x]}} \, dx[/tex]
simplify
[tex]\int\limits^{25}_{-1} {e^{0} \, dx[/tex]
any variable to the power 0 is 1
[tex]\int\limits^{25}_{-1} 1 \, dx[/tex]
integrating 1 gives x
[tex]\left[ \:x \: \right]^{25}_{-1}[/tex]
apply limits
[tex]25 - (-1)[/tex]
add terms
[tex]26[/tex]
[tex]\\ \rm\hookrightarrow \displaystyle\int\limits_{-1}^{25}e^{x-[x]}dx[/tex]
- [x] is x if x is a real number
[tex]\\ \rm\hookrightarrow \displaystyle\int\limits_{-1}^{25}e^{x-x}dx[/tex]
[tex]\\ \rm\hookrightarrow \displaystyle\int\limits_{-1}^{25}e^0dx[/tex]
- e⁰=1
[tex]\\ \rm\hookrightarrow \displaystyle\int\limits_{-1}^{25}dx[/tex]
[tex]\\ \rm\hookrightarrow \left[x\right]_{-1}^{25}[/tex]
[tex]\\ \rm\hookrightarrow 25-(-1)[/tex]
[tex]\\ \rm\hookrightarrow 25+1[/tex]
[tex]\\ \rm\hookrightarrow 26[/tex]