Respuesta :

Answer:

26

Explanation:

[tex]\int\limits^{25}_{-1} {e^{x-[x]}} \, dx[/tex]

simplify

[tex]\int\limits^{25}_{-1} {e^{0} \, dx[/tex]

any variable to the power 0 is 1

[tex]\int\limits^{25}_{-1} 1 \, dx[/tex]

integrating 1 gives x

[tex]\left[ \:x \: \right]^{25}_{-1}[/tex]

apply limits

[tex]25 - (-1)[/tex]

add terms

[tex]26[/tex]

[tex]\\ \rm\hookrightarrow \displaystyle\int\limits_{-1}^{25}e^{x-[x]}dx[/tex]

  • [x] is x if x is a real number

[tex]\\ \rm\hookrightarrow \displaystyle\int\limits_{-1}^{25}e^{x-x}dx[/tex]

[tex]\\ \rm\hookrightarrow \displaystyle\int\limits_{-1}^{25}e^0dx[/tex]

  • e⁰=1

[tex]\\ \rm\hookrightarrow \displaystyle\int\limits_{-1}^{25}dx[/tex]

[tex]\\ \rm\hookrightarrow \left[x\right]_{-1}^{25}[/tex]

[tex]\\ \rm\hookrightarrow 25-(-1)[/tex]

[tex]\\ \rm\hookrightarrow 25+1[/tex]

[tex]\\ \rm\hookrightarrow 26[/tex]

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