The expression x2y - 2xy - 24y can be factored by first factoring out a common factor of y. After the common factor is removed, the remaining factor is a\

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The remaining factor of x^2y - 2xy - 24y is (x - 6)(x + 4)

How to determine the remaining factor?

The expression is given as:

x^2y - 2xy - 24y

Factor out y from the expression

y(x^2 - 2x - 24)

Expand the equation

y(x^2 + 4x - 6x - 24)

Factorize

y(x - 6)(x + 4)

Hence, the remaining factor of x^2y - 2xy - 24y is (x - 6)(x + 4)

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https://brainly.com/question/19386208

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