51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.
To calculate the number of moles use the formula
Number of moles = [tex]\frac{\text{Given Mass}}{\text{Molar Mass}}[/tex]
= [tex]\frac{32.5}{17}[/tex]
= 1.9 mol
4NH₃ + 5O₂ → 4NO + 6H₂O
4 mol of NH₃ react with oxygen to given 6 mole of water.
So 1.9 mol of NH₃ produces = [tex]\frac{1.9}{4}\times 6[/tex]
= 2.85 mol of water
Mass of water = Molar Mass of water × Number of moles of water
= 18 × 2.85
= 51.3 gram
Thus from the above conclusion we can say that 51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.
Learn more about the Moles here: brainly.com/question/15356425
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