a 30kg crate is pulled up a ramp 15m long and 2m high by a constant force of 100n. the crate starts from resta nd has a velocity of 2m/s when it reaches the ramp. what is the frictional force between the crate and the ramp. use the principal of conservation energy.​

Respuesta :

The frictional force between the crate and the ramp is determined as 35.2 N.

Energy lost to frictional force

Apply the principle of conservation energy to calculate the change in the energy of the crate.

Change in energy of the crate = energy loss to friction

P.Ei - K.Ef = E

mgh - ¹/₂mv² = E

where;

  • m is mass of the crate
  • h is vertical height traveled by the crate
  • v is the final velocity of the crate

(30)(9.8)(2) - (0.5)(30)(2²) = E

528 J = E

Frictional force between the crate and the ramp

E = Fd

where;

  • F is the frictional force
  • d is the distance traveled by the crate

F = E/d

F = (528)/(15)

F = 35.2 N

Thus, the frictional force between the crate and the ramp is determined as 35.2 N.

Learn more about frictional force here: https://brainly.com/question/4618599

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