Answer:
Area = (a² -5a) in²
Perimeter = (4a -10) in
Step-by-step explanation:
Let the length of the rectangle be a.
Given that, its width is 5 in less than the length.
So,
length ⇒ a
width ⇒ (a - 5)
First, let's find the area of the rectangle.
Area = length × width
Area = a ( a - 5 )
Solve the brackets.
Area = (a² -5a) in²
Now, let us find the perimeter of the rectangle.
Perimeter = 2 ( l + w )
Perimeter = 2 ( a + a - 5 )
Perimeter = 2 ( 2a - 5 )
Perimeter = (4a -10) in
