The value of x is -23 and the values of AB, BC, and AC are -33, 12 and -21
How to solve the equation and find AB, BC, and AC?
The equations are given as
AB = 13 + 2x
BC = 12
AC = x + 2
Point B is between A and C on Line AC.
So, we have
AC = AB + BC
This gives
x + 2 = 13 + 2x + 12
Evaluate the like terms
x - 2x = 13 + 12 - 2
This gives
-x = 23
Divide by -1
x =-23
Substitute x =-23 in AB = 13 + 2x and AC = x + 2
AB = 13 - 2 * 23 = -33
AC = -23 + 2 = -21
Hence, the value of x is -23 and the values of AB, BC, and AC are -33, 12 and -21
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