The molarity of the zinc chloride solution will be 0.089 M
Mole of 7.24 g ZnCl2 = 7.24/136.286 = 0.5312 mol
Total volume of water used in preparing the solution = 300 + 300 = 600 mL
Molarity of the solution = mole/volume = 0.5312/0.6 = 0.089 M
The molarity of the zinc chloride solution is, therefore, 0.089 M
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