Question

A car is traveling north on a straight road at 20 mys and a drone is flying east at 6 mys at an elevation of 25 m. At one instant the drone passes directly over the car. How fast is the distance between the drone and the car changing 5 seconds later

Answer 1

The distance between the drone and the car will be 20,3 m/s.

What is average velocity?

In physics, velocity is a quantity that identifies the displacement of a body in a given time. Thus, the average velocity measures in an average time interval, the speed of displacement of a body.

With that being said, Suppose that both car and drone starts from 0 and move towards north and east, respectively. So, after T time:

Distance covered by the car, $y = 20.T.m$

Distance cover by the drone, $x = 6.T.m$

Considering the elevations of 25m, the actual distance between them at any T instant:

$A = \sqrt{(20T)^{2} } + (6T)^{2} +25^{2}$

Speed, $V = \frac{ds}{dt} = \frac{[2(20T).20+2(6T).8}{\sqrt{(20.5)^{2}+(6T)^{2}+25^{2} } }$

$V = 20,3 m/s$

So, the distance between the drone and the car will be 20,3 m/s.

See more about mechanics at: brainly.com/question/23561157

#SPJ1