Percent of the original volume that is removed is; 18%
Formula for volume of a box is;
V = lbh
where;
l is length
b is breadth
h is height
Thus;
V_original = 15 * 10 * 8
V_original = 1200 cm³
Volume for each cube removed = 3 * 3 * 3 = 27 cm³
Since there are 8 corners on the box, then 8 cubes are removed.
So the total volume removed is; 8 * 27 = 216
Thus;
Percent of the original volume that is removed is;
216/1200 * 100% = 18%
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