During a collision with a wall, the velocity of a 0.200-kg ball changes from 20.0 m/s toward the wall to 12.0 m/s away from the wall. If the time the ball was in contact with the wall was 0.0500 s, what was the magnitude of the average force applied to the ball

Respuesta :

The magnitude of average force applied to the ball is 128N.

To find the answer, we need to know about the average force.

What's average force?

  • According to Newton's law, average force= change in momentum/time
  • Here, change in momentum= 0.2×20-(-0.2×12) = 6.4 kg m/s
  • Time = 0.05s
  • Average force= 6.4/0.05= 128N

Thus, we can conclude that the average force is 128N.

Learn more about the average force here:

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