The acceleration lasted for 0.007s.
To find the answer, we need to know about the Newton's equation of motion.
What's the Newton's equation of motion that relates initial velocity, final velocity, acceleration, time and distance?
Newton's equations are
- V²-U²= 2aS
- V²-U²= 2aSV= U+at
V= final velocity, U= initial velocity, a= acceleration, t= time and S = distance
What's the acceleration, if the fireshell is accelerated from rest to a velocity of 60.0 m/s over a distance of 0.200 m?
- Here, U= 0m/s, V= 60.0 m/s, S= 0.200 m
60²-0= 2a×0.2= 0.4a
What's the time taken by the fireshell to achieve 60m/s with 9000m/s² acceleration from rest?
- Here, U= 0m/s, V = 60.0 m/s, a= 9000m/s²
- 60= 0+9000t
- t= 60/9000= 0.007 s
Thus, we can conclude that the acceleration of the fireshell lasted for 0.007s.
Learn more about the acceleration here:
brainly.com/question/460763
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