Planet Zoltron takes 32 days to to go once around the Sun.
To find the answer, we need to know about the third law of Kepler.
What's the Kepler's third law?
- Kepler's third law says the square of time period is directly proportional to the cube of the radius of the orbit.
- Mathematically, T²∝a³
What's the time period of planet Zoltron present at 10AU from sun?
- Let T1 , T2 are the time period of Earth and Zoltron.
- a1, a2 are radius of earth and Zoltron orbit respectively.
- As per Kepler's third law, (T1/T2)²= (a1/a2)³
- T2 = (a2/a1)3/2×T1
= (10 AU/ 1AU)3/2 × 1day
= 32 days.
Thus, we can conclude that the planet Zoltron has time period of 2 days.
Learn more about the Kepler's third law here:
brainly.com/question/16705471
#SPJ4
