The dimension of the box should be 1.7×1.7×3.58 in inches, applying minimization of surface area.
Dimensions to Minimize the Surface Area of the Box
It is given that the box is square based with an open top.
⇒ The box has one square and 4 rectangles
Thus, the total surface area of the box is given as,
S= a²+ab+ab+ab+ab
S= a²+4ab ______________ (1)
Here, a is the side of the squared base and length of the rectangular sides of the box, b is the breath of the rectangular sides of the box.
This equation is later used for minimization of the surface area.
Also, the volume, V = a²b
It is also given that volume of the box is 184 in³.
⇒ 184 = a²b _____________ (2)
Forming a One-Variable Equation
From equation (2), b=184/a²
Now, substitute this value of b in equation (1) to get,
S = a² + 4a(184/a²)
S = a² + 4(184/a)
S = a² + 736/a
Minimization of Surface Area to find the Dimension
We require a dimension that will minimize the surface area of the box. Hence, applying minimization surface area, dS/da = 0
dS/da = 2a -736/a²
0 = 2a -736/a²
⇒ 0 = 2a³- 736
2a³ = 736
a³ = 736/2
a³ = 368
a = ∛368
a= 7.17 in
∵V = a²b
184 = (7.17)²b
b = 184/7.17²
b = 184/51.4089
b = 3.58 in
Therefore, 1.7×1.7×3.58 in inches is the required dimension for the box, using minimization of surface area..
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