Question

A car generator turns at 400 rpm (revolutions per minute) when the engine is idling. It has a rectangular coil with 300 turns of dimensions 5.00 cm by 5.22 cm that rotates in an adjustable magnetic field. What is the field strength needed to produce a 24.0 V peak emf

Answer 1

The field strength needed to produce a 24.0 V peak emf is 0.73T.

To find the answer, we need to know about the expression of emf.

What's the expression of peak emf produced in a rotating rectangular loops?

• The peak emf produced in a rotating loops= N×B×A×w
• N= no. of turns of the loop, B= magnetic field, A= area of loop and w= angular frequency
• So, B = emf/(N×A×w)

What's the magnetic field applied to the loop, when rectangular coil with 300 turns of dimensions 5.00 cm by 5.22 cm rotates at 400 rpm produce a 24.0 V peak emf?

• N= 300, A= 5cm × 5.22cm = 0.05m × 0.0522m = 0.00261 m²
• Emf= 24V, w= 2π×400 rpm= 2π×(400rps/60) = 42 rad/s
• Now, B= 24/(300×0.00261×42)

B= 24/(300×0.00261×42) = 0.73T

Thus, we can conclude that the magnetic field is 0.73T.

Learn more about the electromagnetic force here:

brainly.com/question/13745767

#SPJ4